AMC 8 · Test Mode

2001 AMC 8

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Problem 1 · 2001 AMC 8 Easy
Ratios, Rates & Proportions unit-rate

Casey's shop class is making a golf trophy. He has to paint 300 dimples on a golf ball. If it takes him 2 seconds to paint one dimple, how many minutes will he need to do his job?

Show hint
Find the total seconds first, then convert to minutes.
Show solution
  1. Painting takes 2 × 300 = 600 seconds.
  2. 600 ÷ 60 = 10 minutes.
D 10 minutes.
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Problem 2 · 2001 AMC 8 Easy
Algebra & Patterns factor-pairs sum-constraint

I'm thinking of two whole numbers. Their product is 24 and their sum is 11. What is the larger number?

Show hint
List the factor pairs of 24 and check which pair adds to 11.
Show solution
  1. The factor pairs of 24 are 1·24, 2·12, 3·8, 4·6 — only 3 and 8 add up to 11.
  2. The larger of the two is 8.
D 8.
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Problem 3 · 2001 AMC 8 Easy
Arithmetic & Operations division

Granny Smith has $63. Elberta has $2 more than Anjou, and Anjou has one-third as much as Granny Smith. How many dollars does Elberta have?

Show hint
Work down the chain: find Anjou's amount first, then Elberta's.
Show solution
  1. Anjou has one-third of $63, which is $21.
  2. Elberta has $2 more: $21 + $2 = $23.
E $23.
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Problem 4 · 2001 AMC 8 Easy
Number Theory place-value

The digits 1, 2, 3, 4, and 9 are each used once to form the smallest possible even five-digit number. The digit in the tens place is

Show hint (soft nudge)
To make a number small, put the smallest digits on the left — but the units digit has to be even.
Show hint (sharpest)
Push the big digits as far right as the even-ending rule allows.
Show solution
  1. Smallest first three digits are 1, 2, 3. That leaves 4 and 9 for the tens and units.
  2. The units digit must be even, so 4 goes in the units and 9 in the tens: the number is 12394, and the tens digit is 9.
E 9.
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Problem 5 · 2001 AMC 8 Easy
Ratios, Rates & Proportions distance-speed-time estimate-and-pick

On a dark and stormy night Snoopy suddenly saw a flash of lightning. Ten seconds later he heard the sound of thunder. The speed of sound is 1088 feet per second and one mile is 5280 feet. Estimate, to the nearest half-mile, how far Snoopy was from the flash of lightning.

Show hint (soft nudge)
Distance = speed × time gives the feet; then compare with a mile.
Show hint (sharpest)
Two miles is about 10,560 feet.
Show solution
  1. In 10 seconds the sound travels 10 × 1088 = 10,880 feet.
  2. Since 2 miles is 2 × 5280 = 10,560 feet, the distance is closest to 2 miles.
C 2 miles.
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Problem 6 · 2001 AMC 8 Medium
Arithmetic & Operations off-by-one

Six trees are equally spaced along one side of a straight road. The distance from the first tree to the fourth is 60 feet. What is the distance in feet between the first and last trees?

Show hint (soft nudge)
Count the gaps between trees, not the trees themselves.
Show hint (sharpest)
First-to-fourth spans 3 gaps; first-to-last spans 5.
Show solution
  1. From the first tree to the fourth there are 3 gaps, so each gap is 60 ÷ 3 = 20 feet.
  2. From the first to the sixth tree there are 5 gaps: 5 × 20 = 100 feet.
B 100 feet.
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Problem 7 · 2001 AMC 8 Medium
Geometry & Measurement area

To promote her school's annual Kite Olympics, Genevieve makes a small kite and a large kite for a bulletin board display. The kites look like the one in the diagram. For her small kite Genevieve draws the kite on a one-inch grid (shown below). For the large kite she triples both the height and width of the entire grid.

What is the number of square inches in the area of the small kite?

Show hint (soft nudge)
A kite's area is half the product of its two diagonals.
Show hint (sharpest)
Read the diagonal lengths straight off the grid.
Show solution
  1. On the grid the kite's diagonals measure 6 and 7 inches.
  2. Area = ½ × 6 × 7 = 21 square inches.
A 21 square inches.
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Problem 8 · 2001 AMC 8 Medium
Geometry & Measurement spatial-reasoning proportion

To promote her school's annual Kite Olympics, Genevieve makes a small kite and a large kite for a bulletin board display. The kites look like the one in the diagram. For her small kite Genevieve draws the kite on a one-inch grid (shown below). For the large kite she triples both the height and width of the entire grid.

Genevieve puts bracing on her large kite in the form of a cross connecting opposite corners of the kite. How many inches of bracing material does she need?

Show hint (soft nudge)
The cross of bracing is just the kite's two diagonals.
Show hint (sharpest)
Tripling the grid triples each diagonal's length.
Show solution
  1. The small kite's diagonals are 6 and 7 units; tripling the grid makes them 18 and 21 inches.
  2. Bracing needed = 18 + 21 = 39 inches.
E 39 inches.
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Problem 9 · 2001 AMC 8 Medium
Geometry & Measurement area-fraction spatial-reasoning

To promote her school's annual Kite Olympics, Genevieve makes a small kite and a large kite for a bulletin board display. The kites look like the one in the diagram. For her small kite Genevieve draws the kite on a one-inch grid (shown below). For the large kite she triples both the height and width of the entire grid.

The large kite is covered with gold foil. The foil is cut from a rectangular piece that just covers the entire grid. How many square inches of waste material are cut off from the four corners?

Show hint (soft nudge)
The kite fills exactly half of the rectangle that surrounds it.
Show hint (sharpest)
So the waste is the other half — equal to the large kite's area.
Show solution
  1. The large grid is (3×6) by (3×7) = 18 × 21 = 378 square inches.
  2. The kite covers exactly half, so the four corners cut away are the other half: 378 ÷ 2 = 189 square inches.
D 189 square inches.
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Problem 10 · 2001 AMC 8 Medium
Fractions, Decimals & Percents percent-multiplier

A collector offers to buy state quarters for 2000% of their face value. At that rate, how much will Bryden get for his four state quarters?

Show hint (soft nudge)
Four quarters is $1 of face value.
Show hint (sharpest)
2000% means 2000 ÷ 100 = 20 times.
Show solution
  1. Four quarters have a face value of $1, and 2000% is 2000 ÷ 100 = 20 times that.
  2. So Bryden gets 20 × $1 = $20.
A $20.
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Problem 11 · 2001 AMC 8 Medium
Geometry & Measurement coordinate-geometry area

Points A, B, C, and D have these coordinates: A(3, 2), B(3, −2), C(−3, −2), and D(−3, 0). What is the area of quadrilateral ABCD?

ABCD
Show hint (soft nudge)
Plot the points — two of the sides are vertical, so this is a trapezoid.
Show hint (sharpest)
Use ½(b₁ + b₂)·h with the vertical sides as the parallel bases.
Show solution
  1. AB and DC are both vertical, so ABCD is a trapezoid. AB runs from y = 2 to y = −2 (length 4); DC from y = 0 to y = −2 (length 2).
  2. The horizontal gap between them is 6, so area = ½(4 + 2)·6 = 18.
C 18.
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Problem 12 · 2001 AMC 8 Medium
Algebra & Patterns custom-operation

If ab = a + bab, then (6 ♦ 4) ♦ 3 =

Show hint (soft nudge)
Work inside the parentheses first, just like any operation.
Show hint (sharpest)
Order matters: the bottom is a − b, not b − a.
Show solution
  1. First 6 ♦ 4 = (6 + 4)/(6 − 4) = 10/2 = 5.
  2. Then 5 ♦ 3 = (5 + 3)/(5 − 3) = 8/2 = 4.
A 4.
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Problem 13 · 2001 AMC 8 Hard
Fractions, Decimals & Percents proportion

Of the 36 students in Richelle's class, 12 prefer chocolate pie, 8 prefer apple, and 6 prefer blueberry. Half of the remaining students prefer cherry pie and half prefer lemon. For Richelle's pie graph showing this data, how many degrees should she use for cherry pie?

Show hint (soft nudge)
Find how many students like cherry pie first.
Show hint (sharpest)
Each student is worth 360° ÷ 36 = 10° of the circle.
Show solution
  1. Remaining students: 36 − 12 − 8 − 6 = 10, and half prefer cherry, so 5 students.
  2. Each student is 360° ÷ 36 = 10°, so cherry pie gets 5 × 10° = 50°.
D 50 degrees.
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Problem 14 · 2001 AMC 8 Hard
Counting & Probability careful-counting combinations

Tyler has entered a buffet line in which he chooses one kind of meat, two different vegetables, and one dessert. If the order of food items is not important, how many different meals might he choose?

Meat: beef, chicken, pork.
Vegetables: baked beans, corn, potatoes, tomatoes.
Dessert: brownies, chocolate cake, chocolate pudding, ice cream.

Show hint (soft nudge)
Multiply the independent choices: meat × vegetable-pair × dessert.
Show hint (sharpest)
Two different vegetables out of four is a combination: C(4,2) = 6.
Show solution
  1. Meat: 3 ways. Dessert: 4 ways. Two different vegetables from 4 (order doesn't matter): C(4,2) = 6 ways.
  2. Total = 3 × 6 × 4 = 72 meals.
C 72.
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Problem 15 · 2001 AMC 8 Hard
Ratios, Rates & Proportions work-rate unit-rate

Homer began peeling a pile of 44 potatoes at the rate of 3 potatoes per minute. Four minutes later Christen joined him and peeled at the rate of 5 potatoes per minute. When they finished, how many potatoes had Christen peeled?

Show hint (soft nudge)
First find how many potatoes are left when Christen starts.
Show hint (sharpest)
Then they peel together at a combined rate — find how long that takes.
Show solution
  1. In the first 4 minutes Homer peels 3 × 4 = 12, leaving 44 − 12 = 32 potatoes.
  2. Together they peel 3 + 5 = 8 per minute, so the rest takes 32 ÷ 8 = 4 minutes.
  3. In those 4 minutes Christen peels 5 × 4 = 20 potatoes.
A 20.
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Problem 16 · 2001 AMC 8 Hard
Geometry & Measurement folding perimeter

A square piece of paper, 4 inches on a side, is folded in half vertically. Both layers are then cut in half parallel to the fold. Three new rectangles are formed, a large one and two small ones. What is the ratio of the perimeter of one of the small rectangles to the perimeter of the large rectangle?

Show hint (soft nudge)
Track the dimensions: folding the 4×4 square makes a 4×2 rectangle.
Show hint (sharpest)
After the cut, the large rectangle is 4×2 and each small one is 4×1.
Show solution
  1. Folding the 4×4 square in half gives a 4×2 shape; cutting parallel to the fold yields one large 4×2 rectangle and two small 4×1 rectangles.
  2. Perimeter ratio = 2(4 + 1) : 2(4 + 2) = 10 : 12 = 5/6.
E 5/6.
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Problem 17 · 2001 AMC 8 Hard
Fractions, Decimals & Percents percent-multiplier estimate-and-pick

For the game show Who Wants To Be a Millionaire?, the dollar values of each question are shown in the following table (where K = 1000). Between which two questions is the percent increase of the value the smallest?

Question values (K = 1000)
Question12345678
Value1002003005001K2K4K8K
Question9101112131415
Value16K32K64K125K250K500K1000K
Show hint (soft nudge)
Most steps simply double the value — that's a 100% increase, so ignore them.
Show hint (sharpest)
Only 2→3, 3→4, and 11→12 are not doublings; compare those.
Show solution
  1. Almost every step doubles (a 100% jump), so the smallest increase is among the non-doublings: 2→3, 3→4, and 11→12.
  2. 2→3 is 200→300 = +50%; 3→4 is 300→500 ≈ +67%; 11→12 is 64K→125K ≈ +95%.
  3. The smallest is from question 2 to 3 (50%).
B From 2 to 3.
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Problem 18 · 2001 AMC 8 Hard
Counting & Probability complementary-counting

Two dice are thrown. What is the probability that the product of the two numbers is a multiple of 5?

Show hint (soft nudge)
A product is a multiple of 5 only if at least one die shows a 5.
Show hint (sharpest)
It's easier to count the complement: neither die is a 5.
Show solution
  1. The product is a multiple of 5 exactly when at least one die is a 5.
  2. P(neither is a 5) = (5/6)(5/6) = 25/36, so P(at least one 5) = 1 − 25/36 = 11/36.
D 11/36.
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Problem 19 · 2001 AMC 8 Hard
Ratios, Rates & Proportions distance-speed-time graph-interpretation
amc8-2001-19
Show hint (soft nudge)
Twice the speed over the same distance means half the time.
Show hint (sharpest)
So Car N's line should sit twice as high and run half as long as Car M's.
Show solution
  1. Car N is twice as fast, so its (horizontal) speed line sits at twice the height of Car M's.
  2. The same distance at double speed takes half the time, so N's line is half as long — only graph D shows both.
D Graph D.
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Problem 20 · 2001 AMC 8 Stretch
Logic & Word Problems deduction

Kaleana shows her test score to Quay, Marty, and Shana, but the others keep theirs hidden. Quay thinks, "At least two of us have the same score." Marty thinks, "I didn't get the lowest score." Shana thinks, "I didn't get the highest score." List the scores from lowest to highest for Marty (M), Quay (Q), and Shana (S).

Show hint (soft nudge)
Quay can only see Kaleana's score — what must be true for him to be sure two scores match?
Show hint (sharpest)
That fixes Quay = Kaleana; then read Marty's and Shana's thoughts relative to Kaleana.
Show solution
  1. Quay only knows Kaleana's score, so to be certain two match he must equal her: Q = K.
  2. Marty isn't lowest, so M > K; Shana isn't highest, so S < K. Replacing K with Q gives S < Q < M.
  3. Lowest to highest: S, Q, M.
A S, Q, M.
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Problem 21 · 2001 AMC 8 Stretch
Arithmetic & Operations sum-constraint work-backward

The mean of a set of five different positive integers is 15. The median is 18. The maximum possible value of the largest of these five integers is

Show hint (soft nudge)
Mean 15 means the five numbers add to 75.
Show hint (sharpest)
To push one number as high as possible, make the other four as small as the rules allow.
Show solution
  1. Five numbers averaging 15 sum to 5 × 15 = 75.
  2. The median (3rd value) is 18, so the two below it are the smallest distinct positives 1 and 2, and the 4th value is the smallest integer above 18, namely 19.
  3. The largest = 75 − 1 − 2 − 18 − 19 = 35.
D 35.
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Problem 22 · 2001 AMC 8 Stretch
Counting & Probability careful-counting

On a twenty-question test, each correct answer is worth 5 points, each unanswered question is worth 1 point, and each incorrect answer is worth 0 points. Which of the following scores is NOT possible?

Show hint (soft nudge)
Start from the top: what's the maximum score, and the next one just below it?
Show hint (sharpest)
There's a gap right under the maximum that no score can land in.
Show solution
  1. All 20 correct scores 20 × 5 = 100. The next-best is 19 correct plus 1 unanswered: 95 + 1 = 96.
  2. So 97, 98, 99 are unreachable — 97 is the impossible score (90, 91, 92, 95 are all attainable).
E 97.
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Problem 23 · 2001 AMC 8 Stretch
Geometry & Measurement symmetry careful-counting

Points R, S, and T are vertices of an equilateral triangle, and points X, Y, and Z are midpoints of its sides. How many noncongruent triangles can be drawn using any three of these six points as vertices?

RSTXYZ
Show hint (soft nudge)
Many of the small triangles are just rotations or reflections of one another — count distinct shapes, not positions.
Show hint (sharpest)
By symmetry, every triangle you can form matches one found in half of the figure.
Show solution
  1. Choosing 3 of the 6 points gives many triangles, but rotations and reflections make most of them congruent, so only distinct shapes count.
  2. There are exactly four shapes: the big equilateral RST; a small equilateral like XYZ; a 30-60-90 right triangle like R-T-Z (two corners and a midpoint); and an obtuse isosceles like R-X-Z (a corner and two midpoints).
  3. So there are 4 noncongruent triangles.
D 4.
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Problem 24 · 2001 AMC 8 Stretch
Logic & Word Problems careful-counting
amc8-2001-24
Show hint (soft nudge)
Track what's left on each half after the red and blue pairs are used up.
Show hint (sharpest)
Each half starts with 3 red, 5 blue, 8 white; subtract the coinciding pairs and the red-white pairs.
Show solution
  1. Each half has 3 red, 5 blue, 8 white. The 2 red pairs use 2 reds per half (1 red left); the 3 blue pairs use 3 blues per half (2 blue left).
  2. The 2 red-white pairs use that last red and 1 white per half, and the 2 leftover blues must pair with whites (no more blue-blue allowed), using 2 more whites.
  3. That leaves 8 − 1 − 2 = 5 whites per half, which coincide as 5 white pairs.
B 5 white pairs.
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Problem 25 · 2001 AMC 8 Stretch
Number Theory divisibility careful-counting

There are 24 four-digit whole numbers that use each of the four digits 2, 4, 5, and 7 exactly once. Only one of these four-digit numbers is a multiple of another one. Which of the following is it?

Show hint (soft nudge)
The multiple still uses the digits 2, 4, 5, 7, so it stays between 2457 and 7542.
Show hint (sharpest)
That keeps the factor tiny: 2457 × 4 is already too big, so test multiplying by 3.
Show solution
  1. Any such multiple uses the same four digits, so it lies between 2457 and 7542; since 2457 × 4 ≈ 9828 overshoots, the factor can only be 2 or 3.
  2. No doubling of a number in the set lands back in the set, but 2475 × 3 = 7425, which uses exactly 2, 4, 5, 7.
  3. So the number is 7425 (= 3 × 2475).
D 7425.
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